Question

if a,b,c is continued proportional then prov that abc(a+b+c)^(3)=(ab+bc+ca)^(3)

Answer 1

hola there,

(a2 + b2 + c2)/(a + b + c)2 = ( a- b + c)/( a + b + c) 

now we can do cross multiplication

(a2 + b2 + c2) ( a + b + c ) = (a - b + c) (a + b + c )2

a3 + ab2 + ac2 + a2b + b3 + c2b + a2c + b2c +c3 = ( a - b + c) (a2 + b2 + c2 + 2ab + 2bc + 2ca )

a3 + ab2 + ac2 + a2b + b3 + c2b + a2c + b2c +c3 = a3 + ab2 + ac2 + 2a2b + 2abc + 2a2c - a2b - b3 - c2b -2ab2 - 2b2c + 2abc + a2c + b2c + c3+ 2abc + 2bc2 + 2c2a

a3 + ab2 + ac2 + a2b + b3 + c2b + a2c + b2c +c3 - a3 - ab2 - ac2 - 2a2b - 2abc - 2a2c + a2b + b3 + c2b + 2ab2 + 2b2c + 2abc - a2c - b2c - c3 - 2abc - 2bc2 - 2c2a = 0

a3 + ab2 + ac2 + a2b + b3 + c2b + a2c + b2c +c3 - a3 - ab2 - ac2 - 2a2b - 2abc - 2a2c + a2b + b3 + c2b + 2ab2 + 2b2c + 2abc - a2c - b2c - c3 - 2abc - 2bc2 - 2c2a = 0

now solve this 

b( a+ b + c) - ac ( a + b + c) = 0

b = ac

Proved