Question

If a + b is 15 and ab is 108 then a square + b square equal to

Answer 1

As long as ab=48, hence a=48/b (divide both sides by b) Then, at a+b=2 ... there have to be 2 instances of it (because we are taking a square i.e. second ... ·

Answer 2

here is the answer
$(a + b) ^{2} = a {}^{2} + b ^{2} + 2ab$
so
$a {}^{2} + b {}^{2} = (a + b) {}^{2} - 2ab$
ie. (15)^2 - 2(108)
225 - 216
=9

hope it helped uh!!!