If a ball dropped from a tower reaches the ground after 3.5 seconds, what is the height of the tower?
Given: g = –9.8 meters/second2
Answers
Answered by
0
Answer:
Explanation:
S = ut
Answered by
1
Answer:
h=ut+1/2gt^2
U=0 seconds
time=3.5 seconds
g=–9.8 meters/second^2
h=0×3.5+1/2×-9.8×-9.8
= 48.2 metres
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