if a ball up and it comes back to the thrower in 6 seconds what will be the maximum height it will reach
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maximum height is 45 (g=10 m/s)
first I calculated the initial velocity by taking time = 3 sec and the with the initial velocity i found out the distance (s= ut + 1/2 at²)
first I calculated the initial velocity by taking time = 3 sec and the with the initial velocity i found out the distance (s= ut + 1/2 at²)
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