if a≠band the difference between the roots of the polynomials x^2+ax+b and x^2 +bx+a is the same ,then, (1) a+b+4=0.. (2) a+b-4 = 0.. (3) a- b +4 =0..(4) a-b -4=0... which is correct
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Answer:
a + b - 4 = 0
Step-by-step explanation:
The roots of the equation x2 + ax + b are:-
[-a + root(a2 -4b)]/2 and [-a - root(a2 -4b)]/2
Hence their difference = root(a2 -4b)/2
The roots of the equation x2 + bx + a are:-
[-b + root(b2 -4a)]/2 and [-b - root(b2 -4a)]/2
Hence their difference = root(b2 -4a)/2
As we know their difference is equal then
root(b2 -4a)/2 = root(a2 -4b)/2
root(b2 -4a) = root(a2 -4b)
(b2 -4a) = (a2 -4b)
4a - 4b = a2 - b2
4(a - b) = (a - b) (a + b)
4 = a + b
a + b -4 = 0
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