If a bar is equal to 2 i + j + 2 k, bieber is equal to 5 and - 3j + ke, then the length of the compliment vector of
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(2i+2j+3k).(3i+6k+nk)=0 2i.3i + 2j.0j + 3k.(6+n) k =0 6+3(6+n)=0 6+n=-2 n=-8. Therefore the value of n is -8 for the two vectors A ........................
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