Question

if a black body radiates 10 cal/s at 227 C , it will radiate at 727 C =

Answer 1

10cal=227c
727cal=?
227*727/10=c
c=16502.9

Answer 2

Answer:

The power radiated by the black body at 727°C is 160 cal/sec

Explanation:

Given that,

A black body radiates a power of 10cal/s at a temperature of 227°C

$P_{1}=10 cal/s\\ [tex]T_{1}=500K$

We are required to find the power it radiates at a temperature of 727°C

$= > T_{2}=727+273=1000K$

According to Stefan Boltzmann law,the radiative power emitted by a black body is proportional to the fourth power of absolute temperature of the surroundings.Hence,Mathematically it can be written as follows

$= > P∝T^{4}$

Therefore applying proportionality for two situations,we get

$\frac{P_{1}}{P_{2}}=(\frac{T_{1}}{T_{2}})^{4}$

Substituting the known values of power radiated and absolute temperature in the above equation,we get the following

$\frac{10}{P_{2}}=(\frac{500}{1000})^{4} \\ = >P_{2} = 160 \: cal \: s {}^{ - 1}$

Therefore,The power radiated by the black body at 727°C is 160 cal/sec

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