Physics, asked by gyaneshsahoo9432, 1 year ago

If a bulb is 60 w is lighted for 4hrs every day for 30 days then the energy consumed is

Answers

Answered by krimusa7524
3

POWER OF BULB=60 W=60/1000 KW

TIME =4 HOURS

ENERGY CONSUMED IN ONE DAY = P × T

=0.06×4 KWH

SO, ENERGY CONSUMED IN 30 DAYS =0.24××30 KWH

= 7.2 KWH

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