Question

if a bus travelling at 20 m per second is subjected to a steady the acceleration of 5 M per second square how long will it take to come to rest

Answer 1

u= 20m/s
a = 5m/s²
v=0 m/s as rest has no speed
from first equation of motion
v= u + at
0 = 20-5t
-20 /-5 = t
4 = t
therefore 4 seconds are needed to bus to come to rest...
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Answer 2

By applying third equation of motion that is v^=u^+2as
0=400+2*5s
-400=10s
-400/10=s
S=-40