if a bus travelling at 20 m per second is subjected to a steady the acceleration of 5 M per second square how long will it take to come to rest
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3
u= 20m/s
a = 5m/s²
v=0 m/s as rest has no speed
from first equation of motion
v= u + at
0 = 20-5t
-20 /-5 = t
4 = t
therefore 4 seconds are needed to bus to come to rest...
HOPE THIS HELPED PLEASE MARK ME AS BRAINLIEST PLZ AND FOLLOW ME IF POSSIBLE FOR INTERESTING ROCKING CORRECT AND VERIFIED ANSWERS....
a = 5m/s²
v=0 m/s as rest has no speed
from first equation of motion
v= u + at
0 = 20-5t
-20 /-5 = t
4 = t
therefore 4 seconds are needed to bus to come to rest...
HOPE THIS HELPED PLEASE MARK ME AS BRAINLIEST PLZ AND FOLLOW ME IF POSSIBLE FOR INTERESTING ROCKING CORRECT AND VERIFIED ANSWERS....
Answered by
0
By applying third equation of motion that is v^=u^+2as
0=400+2*5s
-400=10s
-400/10=s
S=-40
0=400+2*5s
-400=10s
-400/10=s
S=-40
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