If a car at rest accelerates uniformly to a speed of 144km/h in 20s, how much distance is covered by the car
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initial velocity,u= 0
final velocity,v = 144 km/ h=40m/ s
time,t=20 sec
v=u+a.t
40=0+a.20
a=2 m/s^2
distance,s=u.t+1/2a.t^2
s=0.20+0.5.2.20.20
s=4000m
distance covered by car= 4km
final velocity,v = 144 km/ h=40m/ s
time,t=20 sec
v=u+a.t
40=0+a.20
a=2 m/s^2
distance,s=u.t+1/2a.t^2
s=0.20+0.5.2.20.20
s=4000m
distance covered by car= 4km
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