Question

If a chord AB of ⦿ (O, 20) subtends right angle at 0, find the area of the minor segment

Answer 1

ANSWER :

GIVEN :

Radius(r) = 20 cm

θ = 90°

Area of minor segment (APB) = area of minor sector OAPB - Area of ∆OAB

= (πr²θ)/360° - ½ × OA × OB

= (3.14 × 20 × 20× 90°) /360° - ½ × 20×20

= 3.14 × 400/4 - ½ × 400

= 3.14 × 100 - 200

= 314 - 200

Area of minor segment (APB) = 114 cm²

Hence, the Area of minor segment (APB) = 114 cm²

HOPE THIS ANSWER WILL HELP YOU...

Answer 2

According to the problem given ,

r = 20 , angle = x = 90°

Area of minor segment ACBA

= Area of sector OACBO - Area of ∆OAB

= (πr²x°/360°)-1/2×OA× OB

= [(22 ×20×20×90°)/360°] -1/2×20²

= 2200/7 - 200

= ( 2200 - 1400 )/7

= 800/7 sq units

≈ 114.28 sq units

I hope this helps you.

: )