Question

If a coordinates of the midpoints of the sides of the triangle are (4,2)(0,-1) and (2,-1) find coordinates of its vertices

Answer 1

Answer:

1 sq. unit

Step-by-step explanation:

area of triangle= 1/2 * [ x1*(y2-y3)+x2*(y3-y1)+x3*(y1-y2)]

area of triangle ABC= 1/2* [4*(-1-(-1)) + 0*(-1-2) + 2*(2(-1))]

                                 =1/2*[4*(-1+1)+0+2*(-1)]

                                 = 1/2*[0+0-2]

                                 =1/2* -2

                                 = -1

                                 = 1 sq. unit