if a current of 1 ampere is flowing through a wire then low much electrons are flow per second cross section of the wire
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Answered by
43
I = 1A
t =1s
q = I × t = 1C
no of e = q/total no of e
=1/1.6 × 10^-19
=6.25×10^-18 electrons
t =1s
q = I × t = 1C
no of e = q/total no of e
=1/1.6 × 10^-19
=6.25×10^-18 electrons
manju969:
hii
Answered by
62
Current flowing = 1A
time = 1 second
total charge flown in 1 sec = 1A × 1s = 1 C
Charge on single electron = 1.6 × 10^(-19) C
Total number of electrons in 1C = 1 / 1.6 × 10^(-19) = 6.25×10^(18) electrons.
Number of electrons crossing the cross section per second is 6.25 × 10^(18)
time = 1 second
total charge flown in 1 sec = 1A × 1s = 1 C
Charge on single electron = 1.6 × 10^(-19) C
Total number of electrons in 1C = 1 / 1.6 × 10^(-19) = 6.25×10^(18) electrons.
Number of electrons crossing the cross section per second is 6.25 × 10^(18)
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