If a current of 4.5 amps flows into a 3.5 ohm resistor for 5.5 minuits the energy dissipated is?
Answers
Answered by
0
v=ir
v=3.5 times 4.5
equals 15•75
5.5 min is also 5.5times 60 ..seconds
hence energy is
power times time
=15•75times4•5times5•5times60 joule
=23,388.75joules
v=3.5 times 4.5
equals 15•75
5.5 min is also 5.5times 60 ..seconds
hence energy is
power times time
=15•75times4•5times5•5times60 joule
=23,388.75joules
Attachments:
Similar questions