Question

If a current of 8 ampere flows through a resistance of 30 ohm then calculate the time needed to prepare 12500 calorie amount of heat ?​

Answer 1

Answer:

Given:

• If a current of 8 ampere flows through a resistance of 30 ohm.

Find:

• Calculate the time needed to prepare 12500 calorie amount of heat?

Using formula:

• Using heat formula we can find the time required to prepare 12500 Calorie amount of heat.

Know terms:

1. Heat = (H)
2. Current = (I)
3. Resistance = (R)
4. Time = (T)

★ ${\sf{\underline{\boxed{\red{\sf{H = I^{2} \: R \times T}}}}}}$

Calculations:

⇒ $\bold{12500 = 8^{2} \times 30 \times T}$

⇒ $\bold{T = \dfrac{12500}{64 \times 30}}$

⇒ ${\sf{\underline{\boxed{\red{\sf{T = 6.51 \: minutes}}}}}}$

Therefore, 6.51 minute is the required time.

Answer 2

Given that ,

Current (I) = 8 amp

Resistance (R) = 30 ohm

Heat (H) = 12500 calorie

We know that ,

$\sf \fbox{H = { (I)}^{2} RT}$

Thus ,

$\sf \mapsto 12500 = {(8)}^{2} \times 30 \times T \\ \\ \sf \mapsto T = \frac{12500}{64 \times 30} \\ \\\sf \mapsto T = 6.51 \: \: min$

$\therefore \sf \underline{The \: time \: is \: 6.51 \: min \: }$