Biology, asked by rdpatel257, 5 hours ago

If a diploid cell has 18 chromosomes. How many bivalents are possible to form during the process of cell division

Answers

Answered by DARKIMPERIAL

Answer:

Note that these bivalents have two chromosomes and four chromatids, with one chromosome originating from each parent. In metaphase I, each pair of bivalents (two chromosomes, four chromatids total) align on the metaphase plate.

Answered by prernasinhalm

Answer:

If the diploid cell has 18 chromosomes then 9 bivalents are possible during the cell division process

Explanation:

During the cell division especially during the zygotene stage of meiotic prophase I, the two identical or homologous chromosomes get paired up to form the bivalent or the tetrad structure.

Since two chromosomes form one bivalent, and as mentioned the cell is in the diploid state(2n) and has 18 chromosomes so dividing the no. 18 by 2 will give 9.

This means that the 18 chromosomes in the cell will form 9 bivalents.

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