Math, asked by nehadav4, 10 months ago

If a drunken person walk 2m forward and 1m backward. If one step is of 1m.Then how much steps he should walk to fall in the hole which is 10m from starting point?​

Answers

Answered by indukapoor12282
0

19 steps

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Answered by fluffy46
1

Answer:

26 steps

Step-by-step explanation:

As he moves 2m forward and 1m backward... For 1m to move forward he should be moving 3 steps... So for 8m...complete 3*8 steps... For the last 2m... He will be moving 2 steps.. So totally...

(3x8)+2=26 steps

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