Question

the norm of the vector (0 3 -4) is​

Answer 1

Answer:

5

Step-by-step explanation:

we find the norm of a vector by finding the sum of each element squared and then taking the square root.

| v | = √0²+3²+(-4)²

0² = 0

3² = 9

(-4)² = 16

| v | =√ 0 + 9 + 16

| v | = √25

| v | = 5

so norm of the vector ( 0 , 3 -4 ) is 5

so you can find for any norm of a vector by finding the sum of each element squared and then taking the square root.

Answer 2

Answer:

The norm of the given vector is 5

Step-by-step explanation:

Formula used:

The norm or length of a vector $\vec{r}=x\vec{i}+y\vec{j}+z\vec{k}$ is defined as

$|\vec{r}|=\sqrt{x^2+y^2+z^2}$

Given:

$\vec{a}=0\vec{i}+3\vec{j}-4\vec{k}$

Now,

$|\vec{a}|=\sqrt{x^2+y^2+z^2}$

$|\vec{a}|=\sqrt{0^2+3^2+(-4)^2}$

$|\vec{a}|=\sqrt{0+9+16}$

$|\vec{a}|=\sqrt{25}$

$|\vec{a}|=5$