Question

if a force of 4N acts on body of mass 2kg for 4 sec .find distance travelled in 10 sec after start and also find velocity after force is applied​

Answer 1

S=vit+1/2at^2
S=0+1/2(9.8)(10)^2
S=1/2(9.8)(100)
S=490m

V =S/t
V=490/4
V=122.5 m/s