Question

If a human heart beats once in every 0.8 s, then find the number of times the heart would have beaten in the life of a 20 year old person​

Answer 1

Answer:

The heart of a 20 year old person has beaten 788400000 times.

Explanation:

Here, heart beats once in every 0.8 s.

So, the number of times the heart would have beaten in the life of a 20 year old person

$= \frac{20years}{0.8s} \\ = \frac{20 \times 365\times24\times60 \times 60}{0.8} \\ = 788400000$

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Answer 2

788,400,000timesthe number of times the heart would have beaten in the life of a 20 year old person​,If a human heart beats once in every 0.8 s

Explanation:

In the question, we are given that the average life of an Indian is 60 years

We know that there are 365 days in a year, and 24 hours in one day, so we can write

20years=20×365days

⇒20years=7,300days

⇒20years=7300×24hours

convert hours into minutes and then to seconds, therefore, 1 hr=60 min and 1 min =60 sec

60years=7300×24hours

⇒60years=7300×24×60×60s

⇒60years=630720000s

It is given that the heart beats once in 0.8 second, therefore, the number of times the human heart beats in 20 years will be $\frac{630720000}{0.8}$=788,400,000times

Thus, the human heart beats  788,400,000times in the life of an Indian of 20years if the heart beats once in 0.8 seconds.