Question

If a man 3/4 of his original speed then he reaches 20 min late .Find the actual time taken by him ?

Answer 1

Answer:

Let d be the distance he travelled, t be original (actual) time in minutes and v be original (actual) speed in metres/minute. Then:

$d=\frac{3}{4}v\left(t+20\right)$ (1)

$d=vt$ (2)

Substitute (2) into (1):

$\frac{3}{4}v\left(t+20\right)=vt\:;\:\frac{3}{4}\left(t+20\right)=t\:;\:t+20=\frac{4}{3}t\:;\:t-\frac{4}{3}t=-20;\:-\frac{1}{3}t=-20\:;\:t=60$

Hence the answer.

Hope this helps :)

Step-by-step explanation: