if a no. of n-digits is a perfect square and 'n' is an even number then which of the following is the number of digits of its square root
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no of digits in a perfect square is n
no of digits in a perfect square is n If n is odd then no of digits in its square roots is
no of digits in a perfect square is n If n is odd then no of digits in its square roots is 2
no of digits in a perfect square is n If n is odd then no of digits in its square roots is 2n+1
no of digits in a perfect square is n If n is odd then no of digits in its square roots is 2n+1
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