Question

If a+p=2prove that a cube plus 6ap plus p cube minus 8 =0

Answer 1

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Formula Used :  $(a+b)^3=a^3+b^3+3ab(a+b)$

Answer :

$(a+p)=2$

cubing on both sides , we get,

$=>(a+p)^3=2^3\\\\=>a^3+p^3+3ap(a+p)=8$

$=>a^3+p^3+3ap(a+p)-8=0$

Hence Proved

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