if a regular polygon has 104 diagonals then the no of sides are?
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Hello Dear.
Here is the answer---
Number of Diagonals in the Regular Polygon = 104.
∵ Number of Diagonals = (n - 3)n ÷ 2
Where, n = number of sides in the polygon.
∴ 104 × 2 = n(n - 3)
⇒ n² - 3n = 208
⇒ n² - 3n - 208 = 0
Splitting the Middle Term,
⇒ n² - 16n + 13n - 208 = 0
⇒ n(n - 16) + 13(n - 16) = 0
⇒ (n - 16)(n +13) = 0
⇒ n = 16 and n = -13
∵ Number of sides cannot be -13.
∴ Rejecting n = -13.
Hence, number of sides in the Regular Polygon is 16.
Hope it helps.
Here is the answer---
Number of Diagonals in the Regular Polygon = 104.
∵ Number of Diagonals = (n - 3)n ÷ 2
Where, n = number of sides in the polygon.
∴ 104 × 2 = n(n - 3)
⇒ n² - 3n = 208
⇒ n² - 3n - 208 = 0
Splitting the Middle Term,
⇒ n² - 16n + 13n - 208 = 0
⇒ n(n - 16) + 13(n - 16) = 0
⇒ (n - 16)(n +13) = 0
⇒ n = 16 and n = -13
∵ Number of sides cannot be -13.
∴ Rejecting n = -13.
Hence, number of sides in the Regular Polygon is 16.
Hope it helps.
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