Question

If a ring is made up of 6g diamond the number of atoms present in it are?

Answer 1

The 6 gram diamond has 29,331,858,373 atoms in it.

Explanation:

The diamond has 0.5 moles (6.02×10^23 atoms in a mole) of Carbon in it. A diamond is made entirely of Carbon. Each mole of Carbon-12 (which makes up approximately 99% of carbon) weighs 12 grams

Hope that this will help you...

Mark my answer as brainiest...

Answer 2

Answer:

The number of atoms present in 6g of diamonds is $3.004\times 10^{23}$

Explanation:

Molecular formula of diamond is C, i.e., cabon

Given a ring is made up of 6g diamond.

Thus 6 grams of the diamond is up made of 6 grams of carbon.

Thus the molar mass of carbon = 12.01 g/mol.

Number of moles of carbon is given by

$n=\dfrac{\mbox{mass}}{\mbox{molar mass}} =\dfrac{6}{12.01} \approx 0.499~ \mbox{mol}$

According to Avogadro's number, N(A), the number of constituents in one mole of any substance is equal to $6.02\times 10^{23}mol^{-1}$

Therefore, the number of atoms present in 0.499mol of carbon is

$N = n \times N(A)$

    $=0.499\times 6.02\times 10^{23}$

    $=3.004\times 10^{23}$

Therefore, the number of atoms present in 6g of diamonds is $3.004\times 10^{23}.$

For more problems

https://brainly.in/question/6516860

https://brainly.in/question/6510213