Question

If a rocket-powered sled is accelerated to a speed of 993.2 mph in 1.83 seconds, then what is the acceleration (in ft/s2) and what is the distance that the sled travels (in the most appropriate imperial unit)?

Answer 1

Answer:

Given, initial velocity u=0 m/s,u=0m/s, final velocity v=444 m/sv=444m/s and time t=1.83 st=1.83s

If aa be the acceleration.

Using v=u+atv=u+at,

we get 444=0+a(1.83)444=0+a(1.83)

\implies⟹ a=444/1.83=242.62 \sim 243 m/s^2a=444/1.83=242.62∼243m/s

2