if A + sinB + sinC =3 , then cosA + cosB + cosC=?
dhruvsh:
it's there in most of the 11th standard mathematics textbooks
like rd sharma
secondary school means..?
from 5th to 10th standard
herein the secondary school section means all qns from ncert( 5th to 10th ) texbooks only ...? dont mind am researching on this qns
no
it maybe even icse board or the state board
10th standard Aakash Book
k tq friends
^_^
Answers
Answered by
1
sin A + sin B + sin C = 3
Now, the maximum value of sin function is 1.
Thus, when all sin A , Sin B and sin C are equal to 1 will make up 3
So, sin A = 1 = sin 90°
Thus,
A = B = C = 90°
Therefore,
cos A + cos B + cos C = 0+0+0 = 0
Now, the maximum value of sin function is 1.
Thus, when all sin A , Sin B and sin C are equal to 1 will make up 3
So, sin A = 1 = sin 90°
Thus,
A = B = C = 90°
Therefore,
cos A + cos B + cos C = 0+0+0 = 0
Thanks
ur welcome
Answered by
1
0 take A=B=C= 90 angle then SINA=1=SINB=SINC, THEN COSA=C0SB=COSC=COS90=O.
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