Question

If a six digit number 93p25q is divisible by 88 then find the value of p and q

Answer 1

11*8=88so
2*4=8
we want the last two digits divisible by 4. 93p256. 9+p+5=14+p
3+2+6 =11

14+p-11

p as 8

Answer 2

Answer:

p = 8

q = 6

Step-by-step explanation:

If a six digit number 93p25q is divisible by 88 then find the value of p and q

93p25q to be divisible by 88

88 = 8 * 11

Number should be divisible by 11

9 - 3 + p - 2 + 5 - q should be divisible by 11

9 + p - q  should be divisible by 11

=> p - q = 2

number will be divisible by 8 if last 3 digits are divisible by 8

=> 25q should be divisible by 8

256 is divisible by 8

=> q = 6

p - 6 = 2

=> p = 8

number = 93p25q  = 938256

938256 = 88 * 10662