If a six sided fair die is tossed four times and "3" shows up in all four tosses, the probability of "3" on the fifth trial is
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sample space = 1,2,3,4,5,6,
N(S) = 6
let getting 3 on upper face be event A
A= 1
N(A) = 1
P(A) = 1/6
N(S) = 6
let getting 3 on upper face be event A
A= 1
N(A) = 1
P(A) = 1/6
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