if a square and rhombus stand on the same base prove that the square has the larger area
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hey mate here is your answer⤵⤵
Area of rhombus with same base = a * h where h is perpendicular height. This height can be changed from a to 0 so definitely area on square will be more than area of rhombus. Since 0° < θ < 90°, 0 < sin θ < 1. Therefore, area of the square is greater than that of rhombus, provided both stands on same base.
Hope this will help you✌
Area of rhombus with same base = a * h where h is perpendicular height. This height can be changed from a to 0 so definitely area on square will be more than area of rhombus. Since 0° < θ < 90°, 0 < sin θ < 1. Therefore, area of the square is greater than that of rhombus, provided both stands on same base.
Hope this will help you✌
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