Question

If A = $\left[\begin{array}{ccc}2&1\\5&0\\-1&4\end{array}\right]$ and B = $\left[\begin{array}{ccc}-2&3&1\\4&0&2\end{array}\right]$ then find 2A + B' and 3B' - A.

Answer 1

Answer:

$2A+B^{'}=\left[\begin{array}{ccc}2&6\\13&0\\-1&10\end{array}\right]$

$3B^{'}-A=\left[\begin{array}{ccc}-8&11\\4&0\\4&2\end{array}\right]$

Step-by-step explanation:

if

$A =\left[\begin{array}{ccc}2&1\\5&0\\-1&4\end{array}\right]$

$B =\left[\begin{array}{ccc}-2&3&1\\4&0&2\end{array}\right]$

$2A =\left[\begin{array}{ccc}4&2\\10&0\\-2&8\end{array}\right]$

$B^{'} =\left[\begin{array}{ccc}-2&4\\3&0\\1&2\end{array}\right]$

$2A+B^{'} =\left[\begin{array}{ccc}4&2\\10&0\\-2&8\end{array}\right]+\left[\begin{array}{ccc}-2&4\\3&0\\1&2\end{array}\right]\\\\\\=\left[\begin{array}{ccc}4-2&2+4\\10+3&0+0\\-2+1&8+2\end{array}\right]\\\\\\2A+B^{'}=\left[\begin{array}{ccc}2&6\\13&0\\-1&10\end{array}\right]$

$3B^{'}-A =\left[\begin{array}{ccc}-6&12\\9&0\\3&6\end{array}\right]-\left[\begin{array}{ccc}2&1\\5&0\\-1&4\end{array}\right]\\\\\\=\left[\begin{array}{ccc}-6-2&12-1\\9-5&0-0\\3+1&6-4\end{array}\right]\\\\\\3B^{'}-A=\left[\begin{array}{ccc}-8&11\\4&0\\4&2\end{array}\right]$