Question

if a thermometer reads freezing point of water as 20C AND BOILING POINT AS 150C how much the thermometer read when the actual temperature is 60C

Answer 1

see attachment........

Answer 2

let x = reading of new thermometer ,

then,
( x - 20)/(150-20) = C/100

(x -20)/13 = C/10

( x -20)/13 = 60/10 = 6

x -20 = 78

x = 98