Question

if a train runs at 40 kmph it reaches its destination late by 11 minutes. But if it runs at 50 kmph it is late by 5 minutes only. Find the distance to be covered by the train.​

Answer 1

Step-by-step explanation:

let s1=40kmph

t1=11minearly=11*60=660s

s2=50kmph

t2=5minlate=300s

now,

v1+v2=40/660(1)

v1-v2=50/300(2)

solving them we get distance