If a triangle ABC is right angled at C,then value of cos ( A+B)is
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Since ABC is right angled and angle C is 90°
therefore,
A+B+C=180°
A+B=180° - C
A+B=180°-90°
A+B= 90°
Therefore, cos ( A+B ) = cos 90°
cos ( A+B ) = 0
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