If a two digit number is chosen at random, then the probability that the number chosen is a multiple of 3, is
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Answered by
62
Multiple of three in 2 digit are
12, 15 , 17 ,....,99
using A.P. formula we get
99=12+(n-1)/3
99-12 =(n-1)/3
87/3=n-1
n-1=29
n=30
total no of outcomes =90
P(multiple of 3 in two digit)=30/90
=1/3
12, 15 , 17 ,....,99
using A.P. formula we get
99=12+(n-1)/3
99-12 =(n-1)/3
87/3=n-1
n-1=29
n=30
total no of outcomes =90
P(multiple of 3 in two digit)=30/90
=1/3
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