Question

If the age of a wife is reversed ,the figures represent her husband's age. the husbandis senior to her and the difference between their sum. find the age of wife and husband in the age of years

Answer 1

let a = the 10's digit of the wife's age
let b = the units
:
A wife says if i reverse the digits of my age i will find the age of my husband .
10a+b = the wife's age
10b+a = husband's age
:
He is senior to me and the difference of our ages is equal to the 1/11 of the sum of our age.
(10a+b) + (10b+a) = 11((10b+a)-(10a+b))
11a + 11b = 11((10b+a)-(10a+b))
divide both sides by 11
a + b = (10b+a)-10a+b)
a + b = 10b - b + a - 10a
a + b = 9b - 9a
a + 9a = 9b - b
10a = 8b
a = 
a = .8b
Only one single digit solution possible
b=5, a=4
Find the age of wife ? 45 yrs old