Question

If a two-digit number is divided by the sum of the digits, the quotient is 9. But the number obtained by reducing the digit at the tens place by four times the digit at the units place, leaves the remainder 5 when divided by the sum of the digits of the original number. Find the original number

Answer 1

let the original no be 10x+y

sol. 10x+y/x+y=9.........eq.1
     
     10x-3y/x-3y

Answer 2

2 s answer is 2 is answer