1/(x²-3x+2)+1/(x²-5x+6)=2/3 x≠1,2,3
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=>1/(x^2-3x+2)+1/(x^2-5x+6)=2/3
=>1/(x-1)(x-2)+1/(x-2)(x-3)=2/3
=>( x-3+x-1)/(x-1)(x-2)(x-3)=2/3
=> 2(x-2)/(x-1)(x-2)(x-3)=2/3
=> 2/(x-1)(x-3)=2/3
=>(x-1)(x-3)=3
=> x^2-4x+3=3
=> x^2-4x=0
=> x (x-4)=0
=> x=0,4
=>1/(x-1)(x-2)+1/(x-2)(x-3)=2/3
=>( x-3+x-1)/(x-1)(x-2)(x-3)=2/3
=> 2(x-2)/(x-1)(x-2)(x-3)=2/3
=> 2/(x-1)(x-3)=2/3
=>(x-1)(x-3)=3
=> x^2-4x+3=3
=> x^2-4x=0
=> x (x-4)=0
=> x=0,4
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