if a wire is bent into the shape of a square ,the area of the square is 49 sq.cm . When the wire is bent into a semi circular shape ,find the radius of the semi circle
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heya! here is your answer!!!☺
area of square = a² = 49....( a- side of square)
a = √49
a = 7 cm
therefore the length of wire = 4*7 = 28cm
perimeter of semicircle = π r
22/7 * r = 28
r = 28*6/22
r = 14*6/11
r = 84/11
r = 7.63 cm
hope this helps you...:-)
area of square = a² = 49....( a- side of square)
a = √49
a = 7 cm
therefore the length of wire = 4*7 = 28cm
perimeter of semicircle = π r
22/7 * r = 28
r = 28*6/22
r = 14*6/11
r = 84/11
r = 7.63 cm
hope this helps you...:-)
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