If a/(x-2y+3z) = b/(y-2z+3x) = c/(z-2x+3y) and x+y+z ≠ 0, then prove that each ratio = a+b+c/2(x+y+z)
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Answer:
k
Step-by-step explanation:
let a\(x-2y+3z) = b\(y-2z+3x) = c\(z-2x+3y)
.:. by theorem of equal ratios
k= a+b+c
--------------------------------------------
( x-2y+3z) + (y-2z+3x) + (z-2x+3y)
= a + b + c
-----------------
2x+2y+2z
= a + b + c
-----------------
2(x+y+z)
.:. a. b c
--------------- = ------------------- = -----------------
x-2y+3z y-2z+3z z-2x+3y
= a + b + c
------------------
2(x+y+z)
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