Question

If a^x = b^y = c^c and b^2 = ac, prove that
=1/x+1/z=2/y​

Answer 1

Answer:

let a^x =b^y=c^z=k

now a= k^(1/x) ;b=k^(1/y) ;c=k^(1/z)

and as b^2 =ac; substitute values of a, b, c from above

k^(2/y) = k^(1/x) *k^(1/z) ;

on equating powers we get our desired result

i. e 1/x+1/z =1/y.

Answer 2

Answer:

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