If AA+BB+CC=ABC where A B and C have different digits Detailed answer in Puzzle Pedia Youtube channel Dont spam otherwise i will report ur answer
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Step-by-step explanation:
AA = 10A+1A =11A here 10 and 1 are place values
similarly BB=11B and CC =11C so,
11A+11B+11C = ABC
11(A+B+C) =ABC
here ABC should be multiple of 11 to satisfy.
upon checking with multiple of 11 we get 198 satisfies.
11(1+9+8) = 11(18) =198
so A=1, B=9, C =8
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