if ABB×999=ABC123 where A,B,C are digits find the values of A,B,C
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A = 8
B = 7
C = 6
ABB × 999 = ABC876
=> 877 × 999 = 876123.
If you ask me how I did so.
I multiplied 99 by 77.
You see 99 × 77 = 7623 and 2, 3 at the end of the given problem.
So I multiplied 999 by 177, 277, 377, ... , 877, and the answer is here.
B = 7
C = 6
ABB × 999 = ABC876
=> 877 × 999 = 876123.
If you ask me how I did so.
I multiplied 99 by 77.
You see 99 × 77 = 7623 and 2, 3 at the end of the given problem.
So I multiplied 999 by 177, 277, 377, ... , 877, and the answer is here.
thank q
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