Question

If ΔABC ~ ΔDEF such that AB = 9.1 cm and DE = 6.5 cm. If the perimeter of ΔDEF is 25 cm, then the perimeter of ΔABC is
A. 36 cm
B. 30 cm
C. 34 cm
D. 35 cm

Answer 1

Answer:

ΔABC is an isosceles triangle in which ∠C= 90° . If AC = 6 cm, then AB=

A. 6√2 cm

B. 6 cm

C. 2√6 cm

D. 4√2cm

Step-by-step explanation:

In triangle ABC

Let tge altitude be AD on BC

AC=25cm

AB=25cm

BC=14cm

Therefore DC= 1/2*BC

=1/2*14

=7

By Pythagoras theorem,

AD^2+CD^2=AC^2

AD^2+7^2=25^2

AD^2+49=625

AD^2=625-49

AD^2=576

AD=24

Therefore altitude from A on BC is 24 cm

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Answer 2

Answer:

option no. c) is correct

c) 34cm