A man goes 24 m due west and then 7 m due north. How far is he from the starting point?
A. 31 m
B. 17 m
C. 25 m
D. 26 m
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C. 25 m
Step-by-step explanation:
Given: A man goes 24 m due west and then 7 m due north.
Let A be the starting point and B be 24m west of it and C be 7m north of B. So ABC is a triangle, with ∠B as 90 degrees. and AC as hypotenuse.
So AC² = AB² + BC² = 24² + 7² = 576 + 49 = 625 sq. m.
Therefore AC = root of 625 = 25 m.
So the man is 25m away from his starting point.
Option C is the answer.
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