if ABCD is a trapezium with AB parallel to DC if angle A is 50 degrees and angle B 65 degrees then angle DCB
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Answered by
1
Angle B and Angle DCB are supplementary
hence
Angle DCB = 115 DEGREES
hence
Angle DCB = 115 DEGREES
KarupsK:
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Answered by
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Here, angleDCB+angleB=180(angles on the same side of transversal BC of parallel sides AB and DC)
angleDCB+65=180
angleDCB=180-65
angleDCB=115degree
angleDCB=115 degree
angleDCB+65=180
angleDCB=180-65
angleDCB=115degree
angleDCB=115 degree
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