Math, asked by siri78, 1 year ago

if ABCD is a trapezium with AB parallel to DC if angle A is 50 degrees and angle B 65 degrees then angle DCB

Answers

Answered by KarupsK
1
Angle B and Angle DCB are supplementary
hence

Angle DCB = 115 DEGREES

KarupsK: Mark this answer as brainliest answer
siri78: how can you say it's the answer
Answered by Hetarth4
0
Here, angleDCB+angleB=180(angles on the same side of transversal BC of parallel sides AB and DC)
angleDCB+65=180
angleDCB=180-65
angleDCB=115degree

angleDCB=115 degree
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