If AC is the bisector of angle A and angle C and angle 1 equal to angle 2 , show that angle A equal to angle C
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In a quadrilateral ABCD, if the angle bisectors of angle A and angle C meet on BD, how can I prove that the angle bisectors of angle B and angle D meet on AC?
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Makarand Apte (मकरंद आपटे), Works on Computational Geometry
Answered Sep 25 2017 · Author has 607 answers and 1.7m answer views
The key to prove this is to use the angle bisector theorem, which states that the internal bisector of an angle of a triangle divides the opposite side in the ratio of the sides containing the angle bisected.

Since the bisectors of ∠A∠A and ∠C∠C meet at a common point (say XX) on the diagonal BDBD, it means that the diagonal BDBD is divided in a ratio BX:XCBX:XC which is equal to both AB:ADAB:AD and BC:CDBC:CD. So we have,
ABAD=BCCDABAD=BCCD
Rearranging, we have
1 ANSWER

Makarand Apte (मकरंद आपटे), Works on Computational Geometry
Answered Sep 25 2017 · Author has 607 answers and 1.7m answer views
The key to prove this is to use the angle bisector theorem, which states that the internal bisector of an angle of a triangle divides the opposite side in the ratio of the sides containing the angle bisected.

Since the bisectors of ∠A∠A and ∠C∠C meet at a common point (say XX) on the diagonal BDBD, it means that the diagonal BDBD is divided in a ratio BX:XCBX:XC which is equal to both AB:ADAB:AD and BC:CDBC:CD. So we have,
ABAD=BCCDABAD=BCCD
Rearranging, we have
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