Question

If alfa and beta are the zeros of a polynomial x2-4root3x+3, then find the value of alfa+beta-alfa beta.

Answer 1

Hi friend,


___________________________

Given, œ,ß are the zeros of a polynomial x²-4√3x+3


→we know that œ+ß=-b/a=4√3

ϧ=c/a=3

Now, œ+ß-œß=4√3-3

so, the value is 4√3-3


__________________________


I hope this will help u ;)

Answer 2

Hey there !!!!

P(x) = x²-4√3x+3 

α,β are zeroes of polynomial P(x).

In a quadratic polynomial ax²+bx+c=0

Sum of zeroes α,β is

α+β=-b/a 

Product of zeroes

αβ=c/a.

Now comparing ax²+bx+c with x²-4√3x+3 

we get a=1 b=-4√3 c=3

α+β-αβ=-b/a-c/a = -(-4√3)-3/1= 4√3-3.

So, α+β-αβ=4√3-3.

Hope this helps you ......