Math, asked by aaminasvaliyaveedan, 1 year ago

If alpha and beeta are the zeroes of the polynomial f(x)=x^2-x-k, such that alpha -beeta=9,find k

Answers

Answered by amruth8
1

Hope u understood. K=42.

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abhi9112004: wrong
Answered by abhi9112004
2

f(x)=x²-x-k

on comparing with ax²+bx+c=0

we get a=1,b=-1andc=-k

(alf-bet)²=alf²+bet²-2alf.bet

9²=(alf+bet)²-4alf.bet

81= (-b/a)²-4×c/a

81= 1²-4×-k

81=1+4k

80=4k

k=20.

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