Question

if alpha and beeta are the zeroes of the quadratic polynomial p(x)= 4x^2-5x-1 , find the value of alpha^2 beeta +alpha beeta^2​

Answer 1

Answer:

hk, hkxhxhlxulxulcluhuc

Answer 2

Answer:

5/16

Step-by-step explanation:

lets,find the zeros of the given quadratic equation and those zeros are alpha and beta

4x²-5x-1

=4x²-4x-x-1

4x(x-1)-1(x-1)

4x-1=0 or x-1=0

x=1/4 or x=1

so,alpha is 1/4

beta is 1

(1/4)² (1)+(1/4) (1)I

=1/16+1/4

=1+4/16

= 5/16